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Subscribe to the channel now. Today we're going to make a chemistry video. Today we're going to make a chemistry video. The topic is balancing using the algebraic method.
The topic is balancing using the algebraic method. This is the example. This is the example. In chemistry, In chemistry, this is a chemical reaction or equation. this is a chemical reaction or equation.
It can be distinguished by an arrow. It can be distinguished by an arrow. The reactants are on the left and the products are on the right. The reactants are on the left and the products are on the right.
The first step is to place a letter of the alphabet. The first step is to place a letter of the alphabet. This will be A, This will be A, B, B, C, C, D, D, and E. and E. That's why it's called algebraic.
That's why it's called algebraic. We put letters of preference in alphabetical order. We put letters of preference in alphabetical order. In order.
In order, Now we're going to list the elements. now we're going to list the elements. I'm going to put a list of the elements here, I'm going to put a list of the elements here, that is, that is, silver, silver, hydrogen, hydrogen, nitrogen, nitrogen, and oxygen.
and oxygen. Those four elements go in a list. Those four elements go in a list. So, So, In fact, In fact, the order doesn't matter. the order doesn't matter.
I took them as I saw them. I took them as I saw them. Silver, Silver, hydrogen, hydrogen, nitrogen, nitrogen, and oxygen. and oxygen. Obviously, Obviously, on the right is the same, on the right is the same, silver, silver, hydrogen, hydrogen, nitrogen, nitrogen, and oxygen.
and oxygen. Now let's do the algebraic equations, Now let's do the algebraic equations, that is, that is, the formulas. the formulas.
Look, Look, we have silver, we have silver, we start with it, we start with it, with Ag. with Ag. Here we have one in A.
Here we have one in A. So we put a silver. So we put a silver. There is no silver in B.
There is no silver in B. The arrow is the equal sign. The arrow is the equal sign.
You know that all formulas have an equal sign in algebra and in chemistry. You know that all formulas have an equal sign in algebra and in chemistry. There is no silver here, There is no silver here, there is no here, there is no here, and there is silver here. and there is silver here. This 3 is for oxygen, This 3 is for oxygen, it is silver.
it is silver. What does not have a number is a 1. What does not have a number is a 1. So there is silver and A is equal to E first equation. So there is silver in A is equal to E first equation. The other one, The other one, there is no hydrogen here. there is no hydrogen here, Here there is in B, here there is in B, so I put it here.
so I put it here. The arrow is the equal sign B, The arrow is the equal sign B, hydrogen. hydrogen.
There is none here. There is none here. In water there are two H2O.
In water there are two H2O. So we put two in D, So we put two in D, two hydrogens in the D of finger. two hydrogens in the D of finger.
Nitrogen, Nitrogen, there is none here. there is none here. Here there is nitrogen there in B.
Here there is nitrogen there in B. The arrow is the equal sign. The arrow is the equal sign.
There is nitrogen in C, There is nitrogen in C. There is none here. there is none here.
And in E there is another one, And in E there is another one, so we add more N. so we add more N. And finally the oxygen equation, And finally the oxygen equation.
There are none here. there are none here. There are three oxygens in B. There are three oxygens in B.
We put three Bs. We put three Bs. In C there is one more oxygen.
In C there is one more oxygen. In water H2O there is one more oxygen. In water H2O there is one more oxygen.
In E there are three oxygens. In E there are three oxygens. 3e and now we have the equations. 3E and now we have the equations. These equations are going to be very useful and we circle them because they are very important.
These equations are going to be very useful and we circle them because they are very important. This is very important to get right. This is very important to get right.
We have already made a lot of progress in the exercise. We have already made a lot of progress in the exercise. Now, Now, next step, next step, we are going to list the equations.
we are going to list the equations. We erase this and we can say that this is equation 1, We erase this and we can say that this is equation 1, equation 2, equation 2, equation 3 and algebraic equation number 4. equation 3 and algebraic equation number 4. And we say, And we say, which letter is repeated the most? which letter is repeated the most. Look how many A's for Adrian there are. Look how many A's for Adrian there are.
1, 1, there is no other. there is no other. So, So, that one is useless. that one is useless.
How many E's for elephant are there? How many E's for elephant are there? 1, 1, 2, 2, 3. 3. Very good. Very good. How many D's for finger?
How many D's for finger? 1, 1, 2. 2. C for house? C for house?
1, 1, 2. 2. and B for donkey, And B for donkey? 1, 1, 2 and 3. 2 and 3. So, So, the letter that is most present is B. the letter that is most present is B, 1, 1, 2 and 3 and E, 2 and 3. And E, 1, 1, 2 and 3. 2 and 3. Let's go alphabetically and whatever is on the left, Let's go alphabetically and whatever is on the left, then B is what wins because it is present many times.
then B is what wins because it is present many times. To that value that is present many times, To that value that is present many times, we will always have to give it an initial value. we will always have to give it an initial value. That is up to you. That is up to you.
I always recommend that you give it small numbers, I always recommend that you give it small numbers, 1, 1, 2, 2, 3, 3, or 4. or 4. So, So, tilmer in, till Marin, but I always recommend preferably an even number and the smallest even number is 2. but I always recommend preferably an even number and the smallest even number is 2. Although if you give a 1 to a 3, Although if you give a 1 to a 3, the exercise should work. the exercise should work. I'm going to say that b equals 2. I'm going to say that b equals 2. Now let's check equation 1. Now let's check equation 1. Does it work?
Does it work? No, No, at the moment I don't have a re. at the moment I don't have a re.
Equation 2. Equation 2. Yes, Yes, I'm going to put a dot I'm going to put a dot there that I'm going to use it. there that I'm going to use it. Why? Why?
Because I already have b and I can find the other letter. Because I already have b and I can find the other letter. b equals 2d. b equals 2d.
I'll write it here. I'll write it here. b equals a 2d. b equals a 2d. And let's replace our value.
Let's replace our value. We have b, We have b, it equals 2, it equals 2, and that equals 2d. and that equals 2d.
Let's bring it down. Let's bring it down. So, So, this equation is this.
this equation is this. b equals 2d, b equals 2d, b equals 2d, b equals 2d, b equals 2. b equals 2. I write it down, I write it down, I substitute it. I substitute it, and I bring down the 2. and I bring down the 2. And then, And then, look, look, whenever you see a number with a letter, whenever you see a number with a letter, it's multiplying.
it's multiplying. What is this 2 doing with the D for finger? What is this 2 doing with the D for finger?
Multiplying. Multiplying. On the other side, On the other side, it goes to divide.
it goes to divide. So it will remain as 2, So it will remain as 2, and this 2 goes to divide, and this 2 goes to divide, and we're left with D that's solving. and we're left with D that's solving. Solving means leaving a letter alone.
Solving means leaving a letter alone. And this 2 was in the way, And this 2 was in the way, it went to divide on the other side. it went to divide on the other side. 2 halves 1, 2 halves 1, so the D for dice equals 1. so the D for dice equals 1. I'll put it on the right. I'll put it on the right.
Now I'll check equation 1 again. Now I'll check equation 1 again. Can I use it now? Can I use it now?
No, No, I don't have an A or an E. I don't have an A or an E. I already used this one.
I already used this one. I can use this one. I can use this one.
Look, Look, I have B, I have B, yes, yes, but I don't have C or E so, but I don't have C or E so, let's look at equation number 4. let's look at equation number 4. I have B for donkey, I have B for donkey, right? right? C for house, C for house, no. no.
D for finger, D for finger, yes. yes. And E neither. And E neither.
So, So, what do we do? what do we do? We have to do the following.
We have to do the following. It's said that it's a system of equations. It's said that it's a system of equations. Look, Look, I have B.
I have B. I check it and below I have B and here I don't have C and E. I check it and below I have B and here I don't have C and E. I don't have this one. I don't have this one.
I don't have it. I don't have it. I don't have C and E and I don't have it. I don't have C and E and I don't have it. I'll put a dot on them to let me know that I don't have them.
I'll put a dot on them to let me know that I don't have them. D for donkey is a number. D for donkey is a number.
No problem. No problem. So, So, when you have two equations with two letters that you don't know, when you have two equations with two letters that you don't know, C and C and E and E, C and C and E and E, we have to write them here to make a system of equations.
we have to write them here to make a system of equations. I'm going to do it next. I'm going to do it next, look. Look. B equals C plus C.
B equals C plus C. I've already compacted this equation. I've already compacted this equation.
I'm going to erase it and I'll put a dot on it to show that I'm already using it. I'm going to erase it and I'll put a dot on it to show that I'm already using it. Now I'll write this equation too.
Now I'll write this equation too. It will be 3B equals AC plus D plus 13. It will be 3B equals AC plus D plus 13. So, So, these ones that have two dots, these ones that have two dots, three and four, three and four, I put them together. I put them together.
Three and four, Three and four, three and four, three and four, and I compacted them, and I compacted them, and we're going to substitute. and we're going to substitute. I'll draw a line and we're going to do the following, I'll draw a line and we're going to do the following, substitute what we have.
substitute what we have. Look, Look, B, B, C, C, and E. and E, Yes, yes, I have B equals 2. I have B equals two, I'll put it down here. I'll put it down here.
I'm with this one. I'm with this one. B equals 2. B equals 2. I don't know about C and E neither.
I don't know about C and E neither. This is the equation, This is the equation, the one in the first row. the one in the first row. Now I'll go with the other one.
Now I'll go with the other one. I'll substitute directly. I'll substitute directly.
Check it out. Check it out. 3 asterisk B. 3 asterisk B. We have B.
We have B. It equals 2. It equals 2. Remember that number and letter are multiplication. Remember that number and letter are multiplication. 3 asterisk b which equals 2. 3 asterisk B which equals 2. I don't have c either, I don't have C either.
I'll bring it down. I'll bring it down. I do have D it equals 1 plus 1 and I don't have E it goes down the same as 3. I do have d it equals 1 plus 1. And I don't have e it goes down the same as 3 e I'll draw a line again and we're going to do the following. I'll draw a line again and we're going to do the following. This one is ready.
This one is ready. There should always be two letters and a number on the other side. There should always be two letters and a number on the other side.
So this one goes down to 2 equals C plus E exactly the same, So this one goes down to 2 equals C plus E exactly the same, the one with the dot. the one with the dot. This one, This one, look, look, this number has to be passed to this number. this number has to be passed to this number.
This one is adding plus 1. This one is adding plus one. Here it goes to subtract. Here it goes to subtract.
So this one goes to minus 1 and I have the 6. So this one goes to minus 1 and I have the 6. 6 to 1 leaves us with 5 equals the C of house plus and below the E I write the 13. 6 to 1 leaves us with 5 equals the C of house plus and below the E I write the 13. And this equation is almost ready to find those values. And this equation is almost ready to find those values. Now we have to do the following.
Now we have to do the following. We are going to use a method called addition or subtraction. We are going to use a method called addition or subtraction. It is when you have two equations, It is when you have two equations, two formulas with two letters. two formulas with two letters.
and we have two formulas with two letters c and e and if you notice we have the same And we have two formulas with two letters, C and E. And if you notice, we have the same C above and below. C above and below.
So, So, the goal is to make one positive and one negative. the goal is to make one positive and one negative. How do I make this C or this C negative? How do I make this C or this C negative? I multiply by a minus.
I multiply by a minus. It can be the one above or the one below. It can be the one above or the one below. And I do it with the C because it has no number.
And I do it with a c because it has no number. Here, Here, e does have a number, E does have a number, meaning c is easier. meaning C is easier.
It doesn't need a number, It doesn't need a number, just a minus. just a minus. I'm going to multiply the whole thing above, I'm going to multiply the whole thing above, all by a minus. all by a minus.
So I'll have asterisk 2 minus 2 asterisk c c and minus plus c and that's it. So I'll have asterisk 2 minus 2 asterisk c c and minus plus c and that's it. And this is repeated, And this is repeated, 5 equals c plus 13. 5 equals c plus 13. This equation is going to eliminate a letter, This equation is going to eliminate a letter, look, look, with the calculator. with the calculator. Minus 2 plus 5 or the other way around, Minus 2 plus 5 or the other way around, 5 to 2 gives us a 3. 5 to 2 gives us a 3. Then C is eliminated, Then c is eliminated, that's what we want.
that's what we want. This CC is eliminated, This cc is eliminated, CC is cancelled. cc is cancelled. That's what should always happen.
That's what should always happen. And this 3E, And this 3e, pretend they're elephants. pretend they're elephants. 3 elephants minus elephant leaves us with 2. 3 elephants minus elephant leaves us with 2. Elephants. Elephants.
So, So, it didn't end up that 3 equals 2e and how do I solve for e? it didn't end up that 3 equals 2e and how do I solve for e? Remember that to solve is to leave the letter alone.
Remember that to solve is to leave the letter alone. The e is in the way of the 2. The e is in the way of the 2. 2 is multiplying. 2 is multiplying.
Move it to the other side to divide as a fraction 3 halves and that equals e and use the calculator. Move it to the other side to divide as a fraction 3 halves and that equals e and use the calculator, Don't be scared of fractions, don't be scared of fractions, change it to decimal. change it to decimal.
3 halves the calculator tells us that e has a decimal value, 3 halves the calculator tells us that E has a decimal value, 1.5. 1.5. So there we go. So there we go. In fact, In fact, we're almost done.
we're almost done. Check it out. Check it out. We already have B, We already have B, D and E. D and E which ones are we missing?
Which ones are we missing? We can now use equation number 1. We can now use equation number 1. a is equals e and this is straightforward. A is equals E and this is straightforward. a is equals e it means that a is equal to e so, A is equals E.
It means that A is equal to E. So, A is 1.5. is 1.5. And if you notice, And if you notice, we already have A, we already have A, B, B, D and E.
D and E. What are we missing? What are we missing?
C. C. In other words, In other words, we have to find an equation and repeat one of the ones we already used. we have to find an equation and repeat one of the ones we already used.
It could be this one or this one. It could be this one or this one. This one has C. This one has C. Well, Well, let's go with the shortest one, let's go with the shortest one, this one.
this one. And we'll use it again. And we'll use it again.
Equation 3, Equation 3, B equals C plus. B equals C+. I'll write it here.
I'll write it here. B equals C plus E and we substitute the number 2. B equals C plus E and we substitute the number 2. We don't have C. We don't have C. Plus E equals 1.5.
Plus E equals 1.5. So I solve for C, So I solve for C, that is, that is, the equal sign remains and C should be alone here. the equal sign remains and C should be alone here.
We bring down this 2 and this 15 is adding, We bring down this 2 and this 15 is adding, we pass it with the other number to subtract. we pass it with the other number to subtract. So, So, with the calculator 2 to 1.5 gives us 0.5 and this is equal to C E R. with the calculator 2 to 1.5 gives us 0.5 and this is equal to CER. We already used the equations, We already used the equations, we can clear them.
we can clear them. And now, And now, check, check, we already have all the answers, we already have all the answers, but there should be no decimals. but there should be no decimals. So, So, why did it give us a decimal?
why did it give us a decimal? Because we didn't get the initial letter, Because we didn't get the initial letter, which was B, which was B, right? right?
In other words, In other words, it gave us a decimal. it gave us a decimal. If we had guessed the letter with its correct number, If we had guessed the letter with its correct number, there would have been no decimal. there would have been no decimal. It doesn't matter how it is corrected, It doesn't matter how it is corrected, as long as it gives you a decimal, as long as it gives you a decimal, multiply everything by 2 until the decimals are removed.
multiply everything by 2 until the decimals are removed. In other words, In other words, we will multiply this by 2, we will multiply this by 2, d2, d2, by 2. by 2. And let's check to see if they are removed and we are going to write down the results right away. And let's check to see if they are removed and we are going to write down the results right away. Here I am going to erase the A let's look for the A 1.52 gives us 3. Here I am going to Race the A.
Let's look for the A. 1.52 gives us 3. Perfect. Perfect!
Yes, Yes, 3 were removed. 3 were removed. Now B2. Now B2. Asterisk 2. Asterisk 2 4. Perfect.
Perfect! C gave us the whole number. C gave us the whole number. The results should always be entered here before the formula. The results should always be entered here before the formula.
C5 asterisk 2 on the calculator gives us A1. C5 asterisk 2 on the calculator gives us A1. The one from one asterisk two gives us a two.
The 1 from 1 asterisk 2 gives us A2. And finally E 1.52 gives us a three. And finally E1.52 gives us A3.
And we have the results, And we have the results, three, 3, 4, four, one, 1, 2 and 3. two and three. Let's quickly check if it is balanced. Let's quickly check if it is balanced. Let's list the elements again.
Let's list the elements again. The medium, The medium. Now we have silver, Now we have silver, hydrogen, hydrogen, nitrogen and oxygen.
nitrogen and oxygen. And we do the count. And we do the count. The goal is that what is on the left of the arrow and what is on the right of the arrow gives us exactly the same. The goal is that what is on the left of the arrow and what is on the right of the arrow gives us exactly the same.
We say silver, We say silver, here how many are there? here how many are there? There are three on the left and here there are three on the right. There are three on the left and here there are three on the right. Hydrogens, Hydrogens, 4 hydrogens on the left.
4 hydrogens on the left. And here, And here, look, look, it multiplies in water. it multiplies in water.
2 times 2 equals 4. 2 times 2 equals 4. Very good. Very good. Up to here, Up to here, nitrogen. nitrogen.
Here, Here, this 4 also affects nitrogen. this 4 also affects nitrogen. There are 4 on the left, There are 4 on the left, nitrogens.
nitrogens. And here, And here, waters. waters. Look, Look, here there is 1, here there is 1, but here there is also nitrogen times 3. but here there is also nitrogen times 3. 3 nitrogens plus this 4. 3 nitrogens plus this 4. And finally, And finally, oxygen. oxygen.
3 oxygens equals 4 12. 3 oxygens equals 4 12. And here it is in all the formulas. And here it is in all the formulas. We have to add it up.
We have to add it up. I'll start at the end. I'll start at the end.
3 times 3 equals 9 plus these 2 from water. 3 times 3 equals 9 plus these two from water. 11 plus this oxygen gives us 12. 11 plus this oxygen gives us 12. So it means that everything we did was correct.
So it means that everything we did was correct. This little blue table is for checking, This little blue table is for checking. but everything is perfectly balanced and balanced by the algebraic method M in Manuel Consulting. But everything is perfectly balanced and balanced by the algebraic method M in Manuel Consulting. Subscribe to the channel now, Subscribe to the channel now, here are more of my videos on math, here are more of my videos on math, physics, physics, chemistry, chemistry, statistics, statistics, finance, finance, and calculus explained in a flash, and calculus explained in a flash.
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