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Understanding Molarity in Chemistry
May 8, 2025
Calculating Molarity of Solutions
Definition of Terms
Molarity (M)
: Moles of solute divided by liters of solution.
Solute
: Substance dissolved in a solvent (e.g., salt in water).
Solvent
: Substance that dissolves the solute (e.g., water).
Solution
: Combination of solute and solvent.
Calculation Steps
Convert volume to liters:
Divide milliliters by 1000.
Formula for Molarity
: ( M = \frac{moles , of , solute}{liters , of , solution} ).
Example Calculations
Example 1: Sodium Chloride
Problem
: 0.25 moles of NaCl in 300 mL of solution.
Solution
:
Convert volume: ( 300, mL \to 0.3, L ).
Calculate molarity: ( \frac{0.25}{0.3} \approx 0.83, M ).
Example 2: Sodium Hydroxide
Problem
: 60 grams of NaOH in 250 mL.
Solution
:
Molar mass of NaOH: 40 g/mol.
Convert grams to moles: ( \frac{60}{40} = 1.5, moles ).
Convert volume: 250 mL \to 0.25 L.
Calculate molarity: ( \frac{1.5}{0.25} = 6, M ).
Example 3: Potassium Iodide
Problem
: 700 mg of KI in 200 mL.
Solution
:
Convert mg to grams: 700 mg \to 0.7 g.
Molar mass of KI: 166 g/mol.
Convert grams to moles: ( \frac{0.7}{166} ).
Convert volume: 200 mL \to 0.2 L.
Calculate molarity: ( \approx 0.0211, M ).
Example 4: Ethanol Solution
Problem
: 50 mL ethanol in 400 mL water.
Solution
:
Total volume: 450 mL \to 0.45 L.
Density of ethanol: 0.79 g/mL.
Molar mass of ethanol (C2H5OH): 46.068 g/mol.
Convert mL to grams and then to moles.
Calculate molarity: ( \approx 1.905, M ).
Advanced Examples
Aluminum Sulfate
Concentration of Ions
: Given 0.3 M Al2(SO4)3.
Aluminum cations: ( 0.3 \times 2 = 0.6, M ).
Sulfate ions: ( 0.3 \times 3 = 0.9, M ).
Use dissolution equation for detailed calculation.
Iron(III) Chloride
Problem
: 15 g of FeCl3 in 450 mL.
Solution
:
Molar mass of FeCl3: 162.2 g/mol.
Convert grams to moles and then to moles of Cl−.
Calculate molarity: ( \approx 0.617, M ).
Ammonium Chloride Mass Required
Problem
: 250 mL of 0.75 M NH4Cl.
Solution
:
Convert volume to liters.
Calculate mass using molar mass: 53.492 g/mol.
Answer: 10.03 g of NH4Cl.
Potassium Nitrate Volume Required
Problem
: 8.5 g KNO3 for 0.15 M solution.
Solution
:
Molar mass of KNO3: 101.11 g/mol.
Calculate volume in liters and convert to mL: ( 0.56, L \to 560, mL ).
Tips
Molarity is always moles divided by liters.
Always convert units as needed for consistency.
Understand molar mass and its role in converting grams to moles.
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