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Understanding First Order Rate Law
Aug 14, 2024
Integrated Rate Law for First Order Reaction
Integrated Rate Law Equation
Functional Form
:
(\ln [A]_t - \ln [A]_0 = -kt)
Where:
([A]_t) = concentration at time (t)
([A]_0) = initial concentration
(k) = rate constant
(t) = time
Log Property
:
(\ln \left( \frac{[A]_t}{[A]_0} \right) = -kt)
Exponentiation to Solve
Exponentiate both sides:
(\frac{[A]_t}{[A]_0} = e^{-kt})
Multiply by initial concentration:
([A]_t = [A]_0 e^{-kt})
Graphical Representation
Exponential Decay Graph
:
([A]_t) on y-axis
(t) on x-axis
Key Points
:
Time (t = 0): ([A]_t = [A]_0)
As (t \to \infty): ([A]_t \to 0)
Concept of Half-Life
Definition
Half-Life ((t_{1/2}))
:
Time it takes for concentration to decrease to half its initial value.
Calculating Half-Life
Set ([A]_t = \frac{[A]
0}{2}) when (t = t
{1/2})
Substitute into the equation:
(\frac{[A]_0}{2} = [A]
0 e^{-kt
{1/2}})
Simplification:
(\frac{1}{2} = e^{-kt_{1/2}})
Take natural log:
(\ln \frac{1}{2} = -kt_{1/2})
Solve for (t_{1/2}):
(t_{1/2} = \frac{-\ln(\frac{1}{2})}{k})
(\ln(0.5) = -0.693)
(t_{1/2} = \frac{0.693}{k})
Properties
Constant Half-Life
:
Independent of initial concentration ([A]_0).
Example: If half-life is 10 seconds, remains constant regardless of initial particle count.
Practical Example
Starting with 8 particles
:
Half-life = time to reduce to 4 particles = 10 seconds.
Subsequent Reductions
:
From 4 to 2 particles, another 10 seconds.
From 2 to 1 particle, another 10 seconds.
Conclusion
:
Consistency of half-life across different initial concentrations demonstrates the characteristic behavior of first order reactions.
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