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Calculating Force to Lift with Wedge
Aug 20, 2024
Lecture Notes: Calculating Force to Lift a Block Using a Wedge
Introduction
Topic: Determining the force required to lift an object using a wedge.
Focus: Calculating the minimum force needed to initiate movement (pending motion).
Key Concepts
Reactionary Forces
: R1 and R2 are reactionary forces, calculated as the vector sum of normal and friction forces.
Friction
: Coefficient of static friction is 0.35, and it influences the angle between reactionary and normal force.
Calculations Overview
Forces on the Block
:
Previously calculated forces acting on the block.
Found reactionary forces in terms of the block's weight.
Angle due to friction calculated as 19.2°.
Forces on the Wedge
:
Force applied to the wedge, reaction at the bottom (floor) and top (block-wedge interface).
R2 at the block's bottom equals R2 at the wedge's top (equal and opposite forces).
Diagram and Vector Analysis
Vector sum of forces should equal zero.
Angles
: Crucial for calculating unknown forces.
R3 makes an angle of 19.2° relative to the vertical.
Complementary angles calculated:
71° (90° - 19.2°)
62.71° (90° - sum of two angles)
46.58° (180° - sum of other two angles)
Applying the Law of Sines
Objective
: Find F (force to drive wedge) and R3.
Equations
:
( F / \sin(46.58°) = R2 / \sin(7.71°) = R3 / \sin(62.71°) )
R3
: Calculated using ratio of sines.
Force F
: Calculated using known values of R2.
Results
R3
:
( R3 = 0.942 \times 1373 \times \text{Weight of Block} \approx 1.29 \times \text{Weight of Block} )
Force F
:
( F = 0.770 \times 1373 \times \text{Weight of Block} \approx 1.06 \times \text{Weight of Block} )
Conclusion
The force required to lift the block is slightly more than its weight due to the high coefficient of static friction.
Importance of understanding vector forces and angles in solving mechanics problems.
The explanation was split into two parts due to space constraints, emphasizing the need for detailed breakdowns in complex problems.
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