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Understanding Hybridization of Atomic Orbitals
Sep 1, 2024
Notes on Hybridization of Atomic Orbitals
Introduction to Hybridization
Hybridization
: Combines atomic orbitals to create hybrid orbitals.
Example:
sp3 Hybrid Orbital
: Combination of 1s and 3p orbitals (s1p3).
sp2 Hybrid Orbital
: Combination of 1s and 2p orbitals.
sp Hybrid Orbital
: Combination of 1s and 1p orbital.
d2sp3 Hybrid Orbital
: Combination of 2d orbitals, 1s orbital, and 3p orbitals.
Overview of Orbitals
s-Orbital
:
Shape: Spherical.
Represents the probability of finding an electron within an atom.
p-Orbitals
:
Three types:
px
: Oriented along x-axis.
py
: Oriented along y-axis.
pz
: Oriented along z-axis.
Electron Configuration of Carbon
Electron Configuration
: 1s² 2s² 2p².
Valence Electrons
: Carbon has four valence electrons.
sp3 Hybridization of Carbon
Uses all four orbitals (1s + 3p).
Character
:
25% s character (1 out of 4).
75% p character (3 out of 4).
Energy Level
: Closer to 2p than 2s.
Degenerate Orbitals
: All four sp3 orbitals are of the same energy.
Hund's Rule
: Place electrons one at a time in degenerate orbitals with parallel spins.
sp2 Hybridization
Formation
: One s orbital and two p orbitals (leaving one p unhybridized).
Character
:
33% s character (1 out of 3).
67% p character (2 out of 3).
Energy Level
: Closer to 2p than 2s but less than sp3.
Forms three hybrid orbitals.
sp Hybridization
Formation
: One s orbital and one p orbital (two unhybridized p orbitals).
Character
:
50% s character (1 out of 2).
50% p character (1 out of 2).
Energy Level
: Positioned between s and p orbitals.
Forms two hybrid orbitals.
Bonds Formation
Sigma Bonds
: Formed from hybrid orbitals; every bond contains one sigma bond.
Pi Bonds
: Formed from unhybridized p orbitals.
Bond Strength
:
Triple bonds (1 sigma + 2 pi) are stronger than double (1 sigma + 1 pi) and single bonds (1 sigma).
Sigma bonds are stronger than pi bonds.
Summary of Bonds**
Types of Bonds
:
Single Bond
: 1 sigma bond.
Double Bond
: 1 sigma + 1 pi bond.
Triple Bond
: 1 sigma + 2 pi bonds.
Count Example
:
For a given structure, count sigma (every bond = 1 sigma) and pi bonds (1 for each double bond).
Conclusion
Understanding hybridization is crucial for predicting molecular shapes and bond types.
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