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Pythagorean Identities
Jun 23, 2024
Pythagorean Identities
Introduction to Pythagorean Identities
Three main identities:
( \sin^2(\theta) + \cos^2(\theta) = 1 )
( 1 + \tan^2(\theta) = \sec^2(\theta) )
( 1 + \cot^2(\theta) = \csc^2(\theta) )
First Identity: ( \sin^2(\theta) + \cos^2(\theta) = 1 )
Example 1: Finding ( \cos(\theta) )
Given: ( \sin(\theta) = \frac{4}{5} ) ((\theta) is between 0 and 90 degrees)
Steps:
( \sin^2(\theta) + \cos^2(\theta) = 1 )
( \sin(\theta) = \frac{4}{5} \implies \sin^2(\theta) = \left(\frac{4}{5}\right)^2 = \frac{16}{25} )
( 1 = \frac{25}{25} )
( \cos^2(\theta) = \frac{25}{25} - \frac{16}{25} = \frac{9}{25} )
( \cos(\theta) = \pm \frac{3}{5} )
Since (\theta) is in the first quadrant: ( \cos(\theta) = \frac{3}{5} )
Example 2: Finding ( \sin(\theta) )
Given: ( \cos(\theta) = \frac{8}{17} ) ((\theta) is between ( \frac{3\pi}{2} ) and ( 2\pi ))
Steps:
( \sin^2(\theta) + \cos^2(\theta) = 1 )
( \cos(\theta) = \frac{8}{17} \implies \cos^2(\theta) = \left(\frac{8}{17}\right)^2 = \frac{64}{289} )
( 1 = \frac{289}{289} )
( \sin^2(\theta) = \frac{289}{289} - \frac{64}{289} = \frac{225}{289} )
( \sin(\theta) = \pm \frac{15}{17} )
Since (\theta) is in the fourth quadrant: ( \sin(\theta) = -\frac{15}{17} )
Example 3: Finding ( \cos(\theta) ) with additional conditions
Given: ( \sin(\theta) = \frac{2}{5} ) and (\tan(\theta) < 0)
Steps:
Determine the quadrant:
( \sin(\theta) > 0 \Rightarrow) Quadrants 1 or 2
( \tan(\theta) < 0 \Rightarrow) Quadrants 2 or 4
Intersection: Quadrant 4
Use the identity: ( \sin^2(\theta) + \cos^2(\theta) = 1 )
( \sin(\theta) = \frac{2}{5} \implies \sin^2(\theta) = \left(\frac{2}{5}\right)^2 = \frac{4}{25} )
( 1 = \frac{25}{25} )
( \cos^2(\theta) = \frac{25}{25} - \frac{4}{25} = \frac{21}{25} )
( \cos(\theta) = \pm \frac{\sqrt{21}}{5} )
Since (\theta) is in the fourth quadrant: ( \cos(\theta) = \frac{\sqrt{21}}{5} )
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