[Music] welcome to my channel if you like my video then kindly subscribe like and watch thank you welcome back problem 1-7 so statement is cable will fail when subjected to a tension of 2 kilo newton this is the cable here the tension is 2 kilo newton clear determine largest vertical load p the frame will support and calculate the internal normal force shear force and movement and at cross section through point c for this loading so here you have to find the largest force that can be applied at this point and internal loading at point c so we will start it for first by finding the reaction supports reaction forces at point a so support reaction we will find support reaction reaction first for finding support reactions you have to draw the free y diagram i will just mention the force that will act when you remove this support so if you remove this support so there will be a normal force clear at point a as well as there is a horizontal uh force again in this room the tension t is also available that is given as 2 kilo newton so we will find this largest force and the reaction supports as well so for that we will apply the equilibrium condition the first equilibrium condition is that we will find the uh moment about point a is equal to sum of all moment about point a is equal to 0 and that will give the value of maximum b that can be applied so let's start sum of all moment about point a is equal to zero and taking counterclockwise is positive so you can see the force that is producing movement about point a is p and this p is p into perpendicular distance is this one 0.75 plus this plus this and that will give you 2.25 now you can see that this force is producing counterclockwise movement so this will be positive the second force that is producing moment is t so t into perpendicular distance is this one perpendicular distance is this one r from this point to this point so here this is given as 0.5 and the radius of pulley is 0.5 so this distance is 0.1 so total distance is 0.6 so perpendicular distance t into 0.6 is equal to 0 so as this is producing clockwise so that will be negative clear now you have the value of p is equal to 2.25 minus t is given as 2 kilo newton so 2 into 0.6 is equal to 0 from here you can get the value of largest vertical load p that can be applied and that is equal to 0.53 3 kilo newton now we will move further in order to find the reaction force clear so for that we applied some of all force along x direction is equal to zero and in this direction it is positive so you can see that the two forces that is acting horizontally one is this ax and other is this a y clear so a x and t these are the horizontal force that are acting so a x is negative because it is in negative direction and t is positive and the value of t is 2 kilo newton so from here we get a x is equal to 2 kilo newton clear the second equilibrium condition is sum of all forces along y direction and this is used for finding this vertical force so one vertical force is a y that is acting upward the second vertical force is p that is acting downward and this p is 0.53 their sum must be equal to 0 so a y will be equal to 0.53 kilo newton so we up till now we have find out the largest vertical load and the reaction forces at point e now we will move to find the internal loading at point c for internal loading at point c we will draw the free body free body diagram of this portion ac so at a we have vertical force and horizontal force and at point c there will be a shear force there will be a normal force and there will be a moment let this point is this point is point c this is point a this was a x this is a y this is v c shear force this is n c and there will be a moment reaction moment which is equal to mc clear the distance is also mentioned over here this is 0.75 meter now you can easily apply the equilibrium condition in order to find the internal loading such as shear force normal force and moment so i will start from sum of all forces along x direction is equal to 0 in this direction it is positive so two forces ax and nc are acting clear so minus nc minus ax and ax is equal to 2 kilo newton so minus 2 is equal to 0 so it means that nc is equal to minus 2 kilo newton already we have assumed in this direction nc is negative and this is also negative so it means that nc should be positive and our assumed direction is wrong and we have to take nc in this positive direction now we will move toward finding the vertical forces shear force for that we reply this equation of equilibrium so two forces one is v c that is acting downward so it will be negative and a y which is equal to 0.53 plus 0.53 their sum must be equal to 0 so it means that vc is acting downward okay so vc is equal to 0.53 kilo newton so vc is 0.53 kilo newton and it is acting downward clear okay now this this is a positive value clear and again here you have mentioned vc is downward so it means that this direction of shear force is okay now we will find the movement for that sum of all moment about point c is equal to zero and counterclockwise is positive so at point c there is external moment a reaction moment mc that is clockwise so minus mc and due to this loading a y into perpendicular distance 0.7 and it is producing counter clockwise moment so it will be positive so a y is 0.53 and perpendicular distance is 0.75 their sum must be equal to 0 when you calculate this this mc comes out to be 0.40 kilo newton into meter so these are the internal loading this is normal force this is shear force and this is movement of movement at point c these are the internal loading at point c i hope you have enjoyed the video thank you for watching