[Music] aim to determine the enthalpy of neutralization of a strong acid etcl with a strong base NaOH materials required laboratory stand calorimeter cotton wool stirer small wooden block Beaker 250 ml Beaker 500 mL measuring cylinder 100 ml 1 M HCL 100 ml 1 M NaOH 100 ml thermometer 110° C procedure make a setup of a calorimeter take an expanded wooden box and and fill it with cotton wool transfer 100 ml of 1 molar hydrochloric acid into the beaker using the measuring cylinder place the hydrochloric acid solution into the calorimeter measure the initial temperature of the hydrochloric acid and record the data T 1° [Music] C now transfer 100 ml of 1 molar sodium hydroxide solution in 250 m Beaker using the measuring cylinder now measure the initial temperature of the base sodium hydroxide and record the data same as T1 de C wait for some time for both solutions to attain the constant temperature 28° C now now pour the sodium hydroxide solution into the calor meter that contains 100 ml of HCL place the stirer inside the calorimeter close it and stir the mixture [Music] well measure the maximum temperature of the reaction mixture and note it as the final temperature t 2° c observation the initial temperature of the acid and base t 1° c 28° c the final temperature after neutralization T 2° C 40° C change in temperature delta T T1 - T2 DEC C mass of the mixture solution after neutralization 200 g the water equivalent of a calorimeter WG calculation enthalpy change during neutralization of 100 ml of 1 molar HCL is equal to 200 * W multiplied by T1 - T2 multiplied by 4 .18 where W is the calorimeter constant of the value of 29.1 J value depends on the calorimeter when 1,000 mL of 1 mol HCL is allowed to neutralize 1,000 mL of 1 mol NaOH calculate the heat that is released this amount would be 10 times greater than what was achieved so enthalpy of neutralization of strong acid and base is equal to 200 MTI by W multiplied by T1 - T2 multiplied by 4.18 whole upon 1.0 multiplied by 1, upon 100 JW is equal to 200 * W * by T1 - T2 multiplied by 4.18 upon 1.0 * 100 KJ is equal to 200 * 29.1 * by 28 - 40 * 4.18 whole upon 1.0 * 100 k enthalpy of neutralization of strong acid and base is equal to 2,919 32 KJ result enthalpy change in neutralizing strong acid hydrochloric acid with base sodium hydroxide is 2,99 KJ mole per minus1 precautions the heat changes may occur due to the changes in environmental radiation for thermal insulation cotton should be used the mixture of hydrochloric acid and sodium hydroxide should be stirred carefully carefully record the temperature of mixture and individuals