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Balancing Chemical Equations with Moles
Apr 9, 2025
Using Moles to Balance Chemical Equations
Introduction
Topic:
Balancing chemical equations using moles.
Level:
Higher tier only.
Previous Knowledge:
Counting atoms method to balance equations.
Objective:
Learn to balance equations using moles.
Key Concepts
Moles:
A measure of quantity in chemistry, important for balancing equations.
Relative Formula Mass:
Used to calculate the number of moles.
Example 1: Hydrogen and Chlorine Reaction
Given:
2g of Hydrogen (H)
71g of Chlorine (Cl)
73g of Hydrogen Chloride (HCl)
Steps to Balance:
Calculate moles:
Moles of H = Mass / Relative Formula Mass = 2 / 2 = 1 mole
Moles of Cl = 71 / 71 = 1 mole
Moles of HCl = 73 / 36.5 = 2 moles
Determine the lowest ratio:
Divide all moles by the smallest number (1 in this case):
H: 1/1 = 1
Cl: 1/1 = 1
HCl: 2/1 = 2
Write balanced equation without the number one.
Example 2: Aluminium and Iron Oxide Reaction
Given:
54g of Aluminium (Al)
216g of Iron (III) Oxide (Fe₂O₃)
102g of Aluminium Oxide (Al₂O₃)
168g of Iron (Fe)
Steps to Balance:
Calculate moles:
Al = 2 moles, Fe₂O₃ = 3 moles, Al₂O₃ = 1 mole, Fe = 3 moles
Determine the lowest ratio:
Divide by the smallest number (1):
Al: 2/1 = 2
Fe₂O₃: 3/1 = 3
Al₂O₃: 1/1 = 1
Fe: 3/1 = 3
Write balanced equation using the ratio.
Example 3: Barium Chloride and Aluminium Sulfate Reaction
Given:
1,248g of Barium Chloride (BaCl₂)
684g of Aluminium Sulfate (Al₂(SO₄)₃)
1,398g of Barium Sulfate (BaSO₄)
534g of Aluminium Chloride (AlCl₃)
Steps to Balance:
Calculate moles:
BaCl₂ = 6 moles, Al₂(SO₄)₃ = 2 moles, BaSO₄ = 6 moles, AlCl₃ = 4 moles
Determine the lowest ratio:
Divide by the smallest number (2):
BaCl₂: 6/2 = 3
Al₂(SO₄)₃: 2/2 = 1
BaSO₄: 6/2 = 3
AlCl₃: 4/2 = 2
Write balanced equation using this ratio.
Conclusion
Practice:
Use the method to balance more complex equations.
Additional Resources:
More questions in Vision workbook, link provided.
Goal Achieved:
Ability to balance chemical equations using moles.
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