Aug 2, 2024
A sin(ωt ± φ)
Δx = nλ
Δx = (2n-1)λ/2
I = KA²
I = I1 + I2 + 2√(I1I2)cosφ
(I_max - I_min) / (I_max + I_min)
λD/d
I0 sin²(β)/β²
Δλ/λ = v/c
θ = 1.22λ/D
D/1.22λ
tan(θ_B) = μ
I = I0 cos²θ
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