Jul 12, 2024
log_b(a)
is the power c
such that b^c = a
.log_2 8 = 3
because 2^3 = 8
.log_b(a)
for a > 0
and b > 0
, b ≠ 1
.log_b(b) = 1
, log_b(1) = 0
.log_b(MN) = log_b(M) + log_b(N)
(Product to Sum)log_b(M/N) = log_b(M) - log_b(N)
(Quotient to Difference)log_b(M^k) = k * log_b(M)
(Power Rule)log_b(M) = log_k(M) / log_k(b)
.
log_b(M) = 1 / log_M(b)
.log_a(b) * log_c(a) = log_c(b)
.a^(log_b(c)) = c^(log_b(a))
.log_a(b^(n)) = (1/n) * log_a(b)
.log_b(f(x)) = log_b(g(x))
resulting in f(x) = g(x)
, ensure the domain is positive.log_2(x) > log_2(3)
implies x > 3
because log
base 2 is increasing.log_a(x)
where a > 1
is an increasing function passing through (1, 0).log_a(x)
where 0 < a < 1
is a decreasing function passing through (1, 0).Number of digits in 2^100 using
log`.log
properties extensively to simplify and reduce complex expressions.