Jul 9, 2024
u_x = u cos(╬╕): Initial speed in x-direction.u_y = u sin(╬╕): Initial speed in y-direction.a_x = 0: No acceleration in the x-direction.a_y = -g: Gravity in the y-direction, always acting downwards.T = 2u sin(╬╕) / gu_y = u sin(╬╕), Final Velocity v_y = 0v = u + at0 = u sin(╬╕) - gtt = u sin(╬╕) / gT = 2tH = (u^2 sin^2(╬╕)) / (2g)u_y = u sin(╬╕), Final Velocity v_y = 0v┬▓ = u┬▓ + 2as to solve for displacement H.R = (u^2 sin(2╬╕)) / gR = u^2 (2 sin(╬╕) cos(╬╕)) / gu_x = u cos(╬╕), No X-direction Acceleration.T = 2u sin(╬╕) / gs = ut + 0.5at┬▓ simplify to R = u┬▓ sin(2╬╕) / gu_x = 4i, u_y = 3jH and Range R are equal.y = x tan(╬╕) - (g x┬▓) / (2u┬▓ cos┬▓(╬╕))