Projectile Motion Explained in Hindi

Jul 9, 2024

Projectile Motion

Introduction

  • Projectile Motion is a type of motion under the influence of gravity.
  • Involves motion in a plane (2D motion), which can be analyzed as motion in x (horizontal) and y (vertical) directions.
  • Examples include a ball thrown and trajectories like football kicks.

Fundamental Concepts

  • Plane Motion: Involves both x and y-direction components, unlike straight-line motion which is 1D.
  • Components of Initial Speed:
    • u_x = u cos(θ): Initial speed in x-direction.
    • u_y = u sin(θ): Initial speed in y-direction.
  • Acceleration:
    • a_x = 0: No acceleration in the x-direction.
    • a_y = -g: Gravity in the y-direction, always acting downwards.
  • Constant Velocity in x and changing velocity in y due to gravity.

Time of Flight (T)

  • Formula: T = 2u sin(θ) / g
  • Derivation:
    1. Consider motion in Y direction and point A to B.
    2. Initial Velocity u_y = u sin(θ), Final Velocity v_y = 0
    3. Apply v = u + at
    4. Final Velocity = 0: 0 = u sin(θ) - gt
    5. t = u sin(θ) / g
    6. Total Time of Flight T = 2t
  • Verification with entire motion consideration.

Maximum Height (H)

  • Formula: H = (u^2 sin^2(θ)) / (2g)
  • Derivation:
    1. Consider motion from point A to B in Y direction.
    2. Initial Velocity u_y = u sin(θ), Final Velocity v_y = 0
    3. Apply v² = u² + 2as to solve for displacement H.

Horizontal Range (R)

  • Formula: R = (u^2 sin(2θ)) / g
  • Also expressed as R = u^2 (2 sin(θ) cos(θ)) / g
  • Derivation:
    1. Consider motion in X direction from point A to C.
    2. Initial Velocity u_x = u cos(θ), No X-direction Acceleration.
    3. Time T = 2u sin(θ) / g
    4. Horizontal Displacement s = ut + 0.5at² simplify to R = u² sin(2θ) / g

Velocity Components

  • Initial Velocity: u_x = 4i, u_y = 3j
  • Final Velocity at different points considering presence/absence of gravitational effect.
  • Determining components after a specified time.

Miscellaneous Applications

  • Deriving velocities and angles at different time intervals.
  • Calculating displacement vectors.

Important Properties

  • Range is the same for two different angles θ and 90-θ when U is constant.
    • Proof through Range formula and angle substitutions.

Special Cases

  1. If Maximum Height H and Range R are equal.
  • Derivatives and solving for angles.
  1. Examine situations involving different initial projections and solving for max angles and ranges.

Equation of Trajectory

  • Path in a projectile motion is parabolic.
  • Derivation:
    1. Combine motions in X and Y directions.
    2. Eliminate time factor and integrate Y and X components.
    3. y = x tan(θ) - (g x²) / (2u² cos²(θ))
    • Relates x and y components in projectile motion.
  • Questions might involve comparisons to polynomials and evaluating angles, initial velocity, etc.

Practical Problems

  • Specific problems involving calculations of height, range, and angles from given components.
  • Derivations involving vectors, Path distinction.

Conclusion

  • Understanding of basic projectile motion with formulas for Time of Flight, Maximum Height, and Range.
  • Utilization of equations in problem-solving related to angles, initial velocities, and displacements.
  • Understanding projectile motion involves analyzing vector components and accelerations due to gravity.