Jul 21, 2024
sin(╬╕) = Opposite / Hypotenusecos(╬╕) = Adjacent / Hypotenusetan(╬╕) = Opposite / Adjacentcosec(╬╕) = 1/sin(╬╕)sec(╬╕) = 1/cos(╬╕)cot(╬╕) = 1/tan(╬╕)cosec(╬╕) = 13/12, find all trigonometric ratios
Hypotenuse = 13k and Base = 12ksin(╬╕) = 5/13cos(╬╕) = 12/13tan(╬╕) = 5/12sin and cos values are complementarysin┬▓(╬╕) + cos┬▓(╬╕) = 1sin┬▓(╬╕) = 1 - cos┬▓(╬╕)cos┬▓(╬╕) = 1 - sin┬▓(╬╕)